Kyiv: President of Ukraine Volodymyr Zelensky congratulated leader of ,,Action and Solidarity’’ party Maya Sandu via Twitter for winning presidential election of Moldova.
,,Congratulations Maya Sandu for victory in presidential election of Moldova. I’m looking forward to enhancing relations between Ukraine and Moldova for European future of our nations.’’, Zelensky posted.
Former prime minister of Moldova, leader of ,,Action and Solidarity’’ party Maya Sandu won second round of presidential election with 57.63 % (938 390 votes), followed by current president of Moldova Igor Dodon with 42.37 % (689 980 votes).